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#1 |
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diyAudio Member
Join Date: Nov 2001
Location: Montreal, Canada
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What would the gain of the regular Thorsten/Peter Daniels gainclone be? 220k/10k, so a gain of 22, right?
Also, how high a gain could this design be pushed to? 40, 80, 100? |
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#2 |
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diyAudio Member
Join Date: May 2003
Location: USA
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Actually, with 10k and 220k, the gain is 23... I don't know howhigh I would push the gain, though. (personally, for me, g=23 was higher than I like... but it worked out ok)
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#3 | |
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diyAudio Member
Join Date: Oct 2002
Location: Croatia
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Quote:
Actually, gain is 22. For inverting topology gain is R2/R1. Maximum gain is limited with bandwith you need. Regards |
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#4 |
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diyAudio Member
Join Date: May 2003
Location: USA
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Oops... I was thinking non-inverting... forgot that their circuits were inverting...
Sorry.
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#5 | |
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diyAudio Moderator Emeritus
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Quote:
I am wondering if the actual perfect gain for the gainclone is quite a bit lower then 22, since the average listening level isn't full volume. It might be interesting to figure out what exactly the gain is at the setting that you use on the gainclone in inverting configuration, and setting the same volume level and same gain in non-inverting configuration to compare. Assuming a 100k potentiometer (thorsten's schematic), and the desired listening level is in the middle (linearly in the middle), then the gain would be 220k/(10k+50k) = a gain of 3.667. -- Brian |
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#6 | |
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Previously: Kuei Yang Wang
Join Date: Nov 2002
Location: Somewhere nice on planet earth where censorship of Ideas is frowned upon
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Konnichiwa,
Quote:
Sayonara |
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#7 |
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diyAudio Member
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my sound card kept making my amp clip so i changed feedback resistors. i have 20k and 1.3k or 1.6k, i don't recall. doesn't oscillate though.
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donuts |
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#8 |
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diyAudio Member
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I'm using 250k for feedback, 10k series resistor and 50K log. pot. I don't know about other people, but my source outputs only so much signal that I usually have the pot set at around 28th pos. on 31 detented potentiometer. It sounds pretty good this way and the gain is close to 30.
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www.audiosector.com “Do something really well. See how much time it takes. It might be a product, a work of art, who knows? Then give it away cheaply, just because you feel that it should not cost so much, even if it took a lot of time and expensive materials to make it.” - JC |
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#9 | |
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diyAudio Member
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Quote:
The 100K pot must be regarded as 25K as the assumption must be that the source impedance, say from your CD Player, is low. So: (220)/(10+25) = 6.286 . When wiper is at the top (hold on to your ears) the gain = 22. So likewise when at the bottom, except gain of 22 times zero (no signal to amplify). Now the math are complete! Seriously though, anyone got a diff result? Isn't it interesting that the calculation is different from shunt feedback, where gain is (R1+R2)/R2, whereas series (inverted) feedback is R1/R2. Joe R. PS: Oh yes, my preferred gain for LM3875 is +33dB.
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The "Elsinore Project" DIY Speaker System Webmaster: Custom Analogue Audio, JLTi and... "The Linear Current Loudspeaker" |
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#10 | |
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Previously: Kuei Yang Wang
Join Date: Nov 2002
Location: Somewhere nice on planet earth where censorship of Ideas is frowned upon
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Konnichiwa,
Quote:
Then you get 50K : 50K//10k = 1:7 which in turn is amplified by 22, giving a net of 3.1428, yet the noisegain is as you have pointed out 6.286. As said, it is a complex sort of circuit (simplicity is deceptive) but it works okay, especially if the feedback resistor is increased to 330K, which should avoid the sound degradation observed with a (22k) resistor from negative input to ground. There are a great many ways to skin this particular Dog (I never skin cat's, I love cat's - can't stand dogs though). Sayonara |
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