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#1 |
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diyAudio Member
Join Date: Sep 2010
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Hi folks,
Taken a look at other threads here, but wanted to pose this specific question regarding source output impedance and the following load. Specifically w/ a LM3875 based gainclone I am building. I have built lots of stuff now, but still not very knowledgeable with electronics. I believe it is common practice for source impedances to be much lower than their loads, correct? But I wonder if my situation is acceptable or not: I am planning to use my gainclone without a preamp before it, EXCEPT for my turntable. The turntable will be (ideally) going through a Bottlehead Seduction which I am also building, and which has an output-Z of roughly 5K. I have read that the source load of the gainclone is about 22K. Will these numbers result in terribly degraded performance? If yes, what sort of device can help the gainclone see a much lower impedance at its input? I don't want to have to add a line-stage, if possible (budget!). Would a buffer help with this? If so, can you recommend a cheap DIY buffer option? Thanks in advance-- hopefully this isn't too novice a question for you guys! AT Last edited by tiller; 12th September 2010 at 05:03 AM. |
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#2 |
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diyAudio Member
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There are two types of matching input and output impedances. One is power matching which is often done when you couple output transformers to a speaker. The impedances of transformer and speaker should be the same then. The other is voltage matching which is the common practice between source and amp where the source's output impedance should be smaller 1/10 of the amp's input impedance.
In your case of 5k/22k you waste about 18,5 % of the signal strength, because the voltage drops in relation the impedances. E. g. your source gives a 200 mV signal and the amplifier will only see 162 mV at its input.
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#3 |
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diyAudio Member
Join Date: Sep 2007
Location: Hangzhou - Marco Polo's 'most beautiful city'. 700yrs is a long time though...
Blog Entries: 46
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If your gainclone is non-inverting, there's no particular reason you're limited to 22k input resistance. I'd suggest an input resistance of greater than 50k for a source impedance of 5k - along the lines of pacificblue's suggestion. Increasing the input impedance of a non-inverting gainclone can be done by component substitution or by bootstrapping (adding a modicum of positive feedback). Certainly no need to add a buffer in this situation.
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I think ideas are what you want to get rid of. I don't really like songs with ideas. - Leonard Cohen |
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#4 |
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diyAudio Member
Join Date: Sep 2010
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Hrm, okay, thanks very much!
This is not something I feel comfortable figuring out on my own, and I have not been able to find much information regarding this issue. I wonder if someone could point me in the right direction for increasing the input impedance of the gainclone? It is the Audio Sector kit; I have included the schematic. I know this is real basic stuff, as a matter of fact I have calculated these things before now that I look at it, but I cannot for the life of me remember the math. Would you use the voltage divider equation to calculate Zin? Which resistor is the better one to increase so as to not impact the audio? Thanks again for your help! AT |
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#5 |
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diyAudio Member
Join Date: Sep 2007
Location: Hangzhou - Marco Polo's 'most beautiful city'. 700yrs is a long time though...
Blog Entries: 46
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I see this particular schematic is DC coupled - therefore there's already an asymmetry in the impedances seen from the -ve and +ve inputs. Its generally sound practice to equalize these. In this case though because there's already asymmetry, just change the 20k input resistor to 56k. Does the Bottlehead have a series output cap (not familiar with this design)? My guess is, being a valve unit it does, so then there's no need for any input cap on the gainclone.
Ideally this amp would have a DC blocking cap in series with the 620R resistor, along the lines shown in the National datasheet for the LM3875. If you went this route, then the 20k resistor increases in value to 56k and the 620R goes up to 1k6 when the input resistor changes to 56k. This will result in balanced impedances at both inputs and hence the lowest possible DC offset at the output.
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I think ideas are what you want to get rid of. I don't really like songs with ideas. - Leonard Cohen Last edited by abraxalito; 12th September 2010 at 03:40 PM. |
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#6 |
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diyAudio Member
Join Date: Sep 2010
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Thanks a million abraxalito!
As an aside, are input impedances completely arbitrary then? I mean, I am sure they aren't, so what are the consequences of changing the 20k to a 56k, for example? The original choice to have the input resistor as 20k was based on what, do you think? Just trying to learn a little here... Cheers! AT |
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#7 |
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diyAudio Member
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Along with a highpass filter and "input impedance", the input resistor also forms a time constant with the DC blocking capacitor. Higher value of input resistor means more chance of getting a "pop" noise at startup when the amp is powered on because the input cap takes longer to charge.
If you have a delayed speaker connection (by means of a relay) then this is a non-issue. But for most general-purpose amps, turn-on pop reduction is the reason input impedance has been standardized to 10k for unbalanced inputs and 20k (2x 10k) for balanced ones. Of course, in DIY designs, you are free to pick any values you wish. Try this experiment, but do it at low power and with some cheap speakers, you don't want to damage anything expensive. Put a 2 Megohm input resistor and a 330nF input cap. When the amp is turned on, you will see the speaker cones moving forward (or rearward depending on polarity), then back to the center position. This isn't a "pop" anymore, it's a full-blown DC ramp down already, showing the effects of the time constant made by the large input resistor. This is why it is desirable to keep input impedance as low as the source can accept, speakers don't like that kind of transients.
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"Audio grade" components simply means that they failed at a more critical job. Last edited by Th3 uN1Qu3; 12th September 2010 at 07:57 PM. |
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#8 | |
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Did it Himself
diyAudio Member
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Quote:
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www.readresearch.co.uk my website for UK diy audio people - designs, PCBs, kits and more |
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#9 | |
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diyAudio Member
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Quote:
I was simply saying that for a given size of input cap, increasing the resistor is going to yield a longer time constant. Thing is, the 2Meg/330nF situation actually happened to me (i mistakenly used a 2Meg input resistor instead of a 22k in a small amp i built). But as you know people have a tendency to use rather large input caps, so one more point for small resistor there.I'm not sure about other reasons behind the 10k standard - might as well consult some official docs. I'll be back soon.
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"Audio grade" components simply means that they failed at a more critical job. |
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#10 |
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diyAudio Member
Join Date: Aug 2008
Location: Vancouver, Canada
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Hi,
I agree with abraxalito. Just an addition - the high source impedance and high input impedance will slightly degrade the S/N ratio, at least in theory. Other than that, no problem with your 5k output impedance |
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