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Chip Amps Amplifiers based on integrated circuits 

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9th August 2009, 09:32 AM  #1 
diyAudio Member
Join Date: May 2008

TDA7052A  power, & (real world) heat levels ...Sanity Check sought!
I'm using a TDA7052A to drive a coil that's 9.2 Ohms (the end device isn't important here!)
OK, so I put a 330Hz sinewave into the chip & crank the input level until the signal is showing 3V peak to peak output across the coil  which is about the level I need it at. But at this level, the TDA7052A gets very hot (ie I can only press my finger firmly on the chip's top surface for a second or two). So, are these following figures correct... 3V peak to peak = 1.062V RMS (ie multiply by 0.354 ) Current flowing through coil = V/R, therefore 1.062/9.2 Ohms = 118mA Total power = VI, therefore 1.062 x 0.118 = 125mW So with a 3V peak to peak sine wave across the coil, this TDA7052A is only running at about 125mW, the datasheet says it can output 1W (which is about 8X the level where I already think it is getting too hot!) Have I stuffed up with my calculations...or am I just underestimating what this tiny little package can disappate safely? 
9th August 2009, 09:41 AM  #2 
diyAudio Member
Join Date: Mar 2006
Location: France

Coil use : welder ?
Hello,
If I'm right : you are driving a coil in sinusoidal current. A coil has complex impedance : Z = R + j L 2 Pi 330. But have a look, a coil is charged by current and gives back some voltage in the chip. I do not know how fine is your electronic knowledge but I want let you know it is like get a punch in your head. We do not like that ! Regards, MaxS
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9th August 2009, 11:58 AM  #3 
diyAudio Member
Join Date: May 2008

Ok, I've solved my problem  doh, of course, it's a BTL chip & I was only scoping the positive leg  therefore the output signal is not 3V peak to peak, but 6V peak to peak.
therefore (if my figures are correct)... 6V sine signal peak to peak = 4.24V RMS (ie peak to peak voltage x 0.707) Coil DC resistance is 9.2 ohms and its inductance is 1.7mH , but at 330Hz, overall resistance (impedance) is 9.98 ohms. (http://www.cvs1.uklinux.net/calculators/ ) Therefore current = Voltage/resistance, 4.24V/9.98 ohms = 425mA Power = VI, 4.24V x 0.424mA = 1.8W No wonder it's getting hot ...I need a more powerful chip! 
9th August 2009, 04:19 PM  #4 
diyAudio Member
Join Date: Jan 2009
Location: upper austria/near linz

hello.
what power supply voltage do you use with this opamp? have a look at the datasheet..........with 6v supply and 8 ohm you will get around 1w.........and with 10ohm probably 0,9w . greetings........ 
9th August 2009, 05:08 PM  #5  
diyAudio Member
Join Date: Dec 2002
Location: Hungary/ Budapest

Quote:
Hi, 6V pp is 3Vpeak, which is 2.12Vrms With this voltage you get ca 0.45Wrms... Tamas 

9th August 2009, 05:23 PM  #6 
diyAudio Member
Join Date: May 2008

mjf  I was using 9V to the TDA7052A as supply voltage.
ttako  yes, I think I made a mistake in my previous calculations (I'm rusty which is why I'm posting here for the sanity check!). Let me walk through this with you.... I concur with the 2.12Vrms, but to work out the RMS power, we need at least one more bit of data  either current or resistance. The coil is 9.2 ohms, but at 330Hz the actual total impedance is 9.98 Ohms. So we have a 2.12V RMS signal across an impedance of 9.98 ohms, therefore the current through the coil must be 0.212mA. Power = V x I therefore power through the coil is 450mW (which I guess concurs with your 0.45W!) Have I got it now then? If so, then perhaps I don't need a different (beefier) audio power chip, but at 0.45W it seems very hot  I can't imagine that being twice this hot (1W) is going to be good for it! 
9th August 2009, 06:00 PM  #7 
diyAudio Member
Join Date: May 2008

Just a quick typo in that last post (& the edit button seems to have gone?), it should have read...
So we have a 2.12V RMS signal across an impedance of 9.98 ohms, therefore the current through the coil must be 212mA. 
11th August 2009, 01:46 AM  #8 
diyAudio Member
Join Date: Mar 2008

This thing is rated for 85 degrees, which would be pretty hot if you touch it. Best to check with a thermometer.
And if you're paranoid, just heatsink it. Though I doubt it'd be necessary. 
11th August 2009, 12:17 PM  #9 
diyAudio Member
Join Date: Jul 2004
Location: Scottish Borders

go and read some literature on power amplifier driving an inductive load.
Start with ESP site. He shows just how bad the amplifier dissipation can become when the reactance starts to exceed 30degree phase.
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regards Andrew T. 
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