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Old 3rd November 2008, 07:18 PM   #1
Ted205 is offline Ted205  United Kingdom
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Default BufferPreamp with servo

Hi guys.

I'm working on a little buffer Preamp to sit in front of my chip amp (lm4780 parallel setup). This is one channel.

The values used are not necessary the values i will use as i haven't made a prototype yet. I'm a newbie so the design might not be up to much (especially the pcb layout ).

I would very much appreichiate you opinions

thanks

Ted
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Old 3rd November 2008, 07:20 PM   #2
Ted205 is offline Ted205  United Kingdom
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Default PCB

The PCB:
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Old 4th November 2008, 04:14 PM   #3
AndrewT is offline AndrewT  Scotland
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C2 is connected to the wrong end of R9.
What are R10 and R11 doing?
Why is R8 so much bigger than R9.
Why is C2 so much different from C3.

Don't mix your Signal grounds and Power grounds.

Why do you need a buffer with the chipamp?
It should be at the output of the previous source.
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Old 5th November 2008, 10:44 AM   #4
Ted205 is offline Ted205  United Kingdom
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thanks for the help andrew.

the Servo values were derived from the info in this topic here.
It simulated well but i haven't tried it in the real world yet.

The star grounding scheme is divided into three (see attached). Two sections were intended to be the clean gnd which connect to the power supply ground. I'm not sure how effective this is

I'm using the buffer (half the NE5532P) as the source will not always have be consistent (i.e guitar and or various pedals, laptop, cd player etc.)

I've removed R11 and put it at the input to the buffer at 1kohm for RF interference immunity along with a 330pf cap parrallel to ground.

The NE5532p will also be replaced with the LM4562 but i dont have it in my parts library


The learning continues

Cheers.
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Old 5th November 2008, 12:19 PM   #5
AndrewT is offline AndrewT  Scotland
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Default correctable offset.

look at U1b.
the opamp tries to adjust the output so that both the input pins are at the same voltage.
Lets put 150mV on pin5 (from U1a).
with a gain of 2times the output will sit at 300mV.
The 1k+1k divider will have 150mV at the junction. This makes pin5=pin6 for voltage.

Pin6 of U4 will have to sit at [115+15+1] / 1 * 150mV=19.65V.
To produce this output the U4 supply will have to be ~+-22Vdc.
Your +-15Vdc supplies will allow correction of ~100mV of input offset.

Q.) is there any error in my arithmetic/logic?
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Old 5th November 2008, 07:18 PM   #6
Ted205 is offline Ted205  United Kingdom
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I can up the regulators to 18v, so all opamps run at the same voltage. and the servo range increases
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Old 6th November 2008, 09:46 AM   #7
AndrewT is offline AndrewT  Scotland
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Hi,
with V1=1V, what is the voltage on pin6 of U4?
What about all the component values you have chosen? Some seem very odd.
The last thing you need to do is change the supply voltage.
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Old 6th November 2008, 10:17 AM   #8
Ted205 is offline Ted205  United Kingdom
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from the simulation

v1 = 1v

u4 pin 6 = 261.228 v

voltage after R8 = 1.001v

voltage at the output from the circuit = 389uV.

Which component values do you not like ?
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Old 6th November 2008, 10:32 AM   #9
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Maybe a good coupling cap between the LM4780 and the preamp is enough. Scrap the dc servo. Might even sound better !
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Old 6th November 2008, 10:37 AM   #10
Ted205 is offline Ted205  United Kingdom
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i think you might be wright
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