4000.1

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That is generally recommended to supply voltage to the high-side of the 21844, not to the positive rail. A 9v battery with very low current capacity is all that's needed. The 1 ohm resistor is there in case there is voltage present on the 21844 (there should be none). It should prevent the 9v battery from exploding.
 
So to connect the battery, I decided, after reading this thread: "DD Z2 bursts output transistors".
Battery negative terminal to negative terminal of negative rail cap.
Battery positive terminal to positive terminal of negative rail cap.
Is that what you did?
Maybe I misunderstood something.
I have 4 218844 on the board. Should I connect the battery in turn to each of them?
 
There is a high-value feedback resistor that connects between the output of the amp to the input pin of the drive board. Desolder and lift one end of it. Does that restore the drive signals that you had before you installed the FETs?

This should not be done with the rectifiers in the circuit. I'm assuming that you have them out of the circuit.

You may need to add a 10k resistor between pins 1 and 2 of the TL072.
 
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Removed rectifier diodes and resistor 240K. Here's what he measured::
 

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The scheme of my AMP largely coincides with this scheme (only here instead of + - RAIL, denoted + VCC2 and - VEE2 and I have 4 pieces 21844).
Now in my AMP, diodes, forming + -RAIL are extracted. But -RAIL + 12V, with a separate transformer winding, after rectification and amplification are fed into the circuit, including on 21844.
Perry, are you sure that to include a 9V battery between GROUND and -RAIL (-VEE2) is the right solution?
 

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