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Old 1st October 2012, 06:12 AM   #1
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Default Wiring 5-pin DIN to RCA

I'm trying to re-wire my 5 pin DIN to an RCA cable but I'm stuck...

ive stripped the RCA cables, which have the outer and core wires
and the DIN cable which looks the same on the inside, but there are more outer wires have "more" wire to them. Will this be an issue at all when I've soldered the wires together??

Also, what do I do about the ground wire? it goes into the DIN cable with the left and right channels on the turntable end, but disappears once its inside the cable, or does it become the extra outer wire???

Help please
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Old 1st October 2012, 09:05 AM   #2
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This will depend on the wiring of the device into which you're plugging the 5 pin DIN. For example, in my tonearm, the DIN plug has (in order) L-hot, L-cold, tonearm ground, R-cold, R-hot. So I have two coaxial cables plus an extra ground wire coming out. The coaxial shields are attached to the appropriate "cold" pins, the inner conductors to the appropriate "hot" pins, and the tonearm ground wire is fixed to my preamp chassis. But this is specific to this particular unit. Other electronics may use the DIN connector as a balanced output (or input) in which case you still have "hot" and "cold" connections which may require a two conductor plus shield wire for each channel, with the shields tied together and connected to the chassis at the "sending" end.

Time to pop the cover and do some tracing!
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Old 6th October 2012, 09:14 PM   #3
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I'm going to have it plugged into two female rca plugs which goto a y splitter and then the mono plug on my receiver.

Here is my setup:
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This is where the wires go into the din cable. the black wire is what goes to the tone arm
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