How to calculate RIAA correctly?

[jackinnj]

Originally posted by Onvinyl
So, anybody who can shine light on the passive riaa case I asked yesterday?
greets,
Rüdiger

Borberly descirbes the passive RIAA in Audio Amateur 4/84 and 1/85. He references articles by Jung and Marsh in those articles. Erno has many of his articles archived on his site (but I don't know if those from the 1980's are there.) www.borberlyaudio.com

Tritschler had an article on passive RIAA in AX -- October 2003 -- the acuracy is very, very good -- a pair of boards is $49 but their (Tritschler) website went off the air a few weeks ago.

In Tritschler's article he used 417a's or their equivalent (5842?)-- but their boards used 6DJ8's.

[Onvinyl]

Originally posted by jackinnj


Borberly descirbes the passive RIAA in Audio Amateur 4/84 and 1/85. He references articles by Jung and Marsh in those articles. Erno has many of his articles archived on his site (but I don't know if those from the 1980's are there.) www.borberlyaudio.com

Tritschler had an article on passive RIAA in AX -- October 2003 -- the acuracy is very, very good -- a pair of boards is $49 but their (Tritschler) website went off the air a few weeks ago.

In Tritschler's article he used 417a's or their equivalent (5842?)-- but their boards used 6DJ8's.

Hi,
it's nice to answer, but, as it concerns me, I asked the question 2,5 years ago, I'm done...

Rüdiger

[Pjotr]

Hi,

If you want to simulate your circuit in PSpice you can use a Laplace source for the inverted RIAA function:

(1+tau_1*S)*(1+tau_3*S)/(1+tau_2*S)

And if you want to incorporate the 3.18 us time constant:

(1+tau_1*S)*(1+tau_3*S)/((1+tau_2*S)*(1+tau_4*S))

Both describe exactly the inverse RIAA and have a gain of 0 dB at 0 Hz.

tau_1 = 3180u
tau_2 = 318u
tau_3 = 75u
tau_4 = 3.18u

Cheers