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#1 |
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diyAudio Member
Join Date: Jun 2008
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#2 |
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diyAudio Moderator
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Pretend R2 and C2 are a single reactance. Call it Z2. Now, Z2 is in series with C1. Call C1's reactance Z1. The impedance of that branch is thus (Z1 + Z2) in parallel with R1. In reverse, the impedance is (Z2 + Z1) in parallel with R1. So, does the order matter?
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“There are no greater liars in the world than quacks, except for their patients.” - Benjamin Franklin |
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#3 |
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diyAudio Member
Join Date: Jun 2008
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Exactly what I told him. =)
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#4 |
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diyAudio Member
Join Date: Mar 2005
Location: Near Gothenburg, the westcoast of Sweden
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Thzar
I could not resist this one You and your "dude mate" did the same drawing exept he was standing on his head, thats why it was different drawn. ti hi hi @Sy As a moderator you are very nice to not laugh to us foreigners.
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Cheers// Ove |
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#5 |
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Richard Murdey
diyAudio Member
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Yes, it will work. Series impedances are commutative. (a+b=b+a)
edit: this is a useful trick for finessing circuit board layouts Last edited by rjm; 5th September 2010 at 11:20 PM. |
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