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#391 | |
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diyAudio Member
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Quote:
__________________
"Second Law is a bitch." - SY “Not to worry, audiophiles don't normally get past the Gate anyway.” - rdf |
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#392 | |
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diyAudio Member
Join Date: Mar 2009
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Quote:
L. Last edited by coluke; 28th August 2012 at 01:38 PM. |
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#393 |
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diyAudio Member
Join Date: May 2011
Location: Virginia
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Good Morning everyone. Another day, another schematic.
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#394 | |||||
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diyAudio Member
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Sorry everyone. Post #391 was a glitch.
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Quote:
You can’t realistically have 2/10 d. Celcius resolution temp. mapping of a surface divided into 25x25um areas and following the dynamic variations of the temp at ~1kHz of all these “pixels” with other methods. All this at a very reasonable price and minimum complexity for a manufacturer or researcher. But still very expensive for the hobbyist. (That’s why the talking turned to the IR spot thermometer). ![]() Quote:
:"Emissivity + Reflectivity = 1" You want to maximize emissivity for to have correct IR temp. measurement. You have to minimize reflectivity to achieve this (shiny aluminum is very reflective). A trick to achieve a spot with max. emissivity (~1 ) on any material, is to drill a blind hole on it with a depth > 2-3d. IR temp. measurement into this spot is really very close to the true local temperature. Quote:
Did they verify the wavelength? Quote:
Raising the temp of the whole opamp, will worsen the dynamic temp. unbalance. A specific subcomponent when variably heated due to it’s I*R will find it more difficult to get rid of it’s thermal energy through the hotter surrounding mass. The delta temp. with another subcomponent (less I*R loaded) will thus increase. George
__________________
"Second Law is a bitch." - SY “Not to worry, audiophiles don't normally get past the Gate anyway.” - rdf |
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#395 | |
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diyAudio Member
Join Date: May 2011
Location: Virginia
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#396 |
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diyAudio Member
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gpapag,
Thank you for the explanations George. I actually follow this quite well except my math is more than rusty... I am glad you pointed out the fallacy of increasing the temperature to control temperature as this just seemed completely incorrect to me. By doing that you have just shot yourself in the foot by what appears to be decreasing your chances of dissipating the rising die temperature to a lower stable temperature. Wouldn't you be better off using a direct contact heat exchanger, a finned heat sink than using air as the direct transfer function? I only suggested the thermocouple as they are so cheap and attached directly to the die with a simple hand held meter you would have a very instantaneous reading of temperature rise. You could also drill a hole as you stated and insert the thermocouple into that hole. I had not seen a hand held with that resolution of depth of field. By drilling the hole you would appear to have two affects, one being the properties of the cavity depth to width and the second being a much thinner substrate that has a time lag in response to the actual temperature change internal to the device. Am I following what you are saying properly? Thanks again. Steven |
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#397 | |
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diyAudio Member
Join Date: Jan 2004
Location: away
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Quote:
Interchip dynamics will not change unless the gradient to the outside world is different for each chip. If for example, one die's heat must go past the other to get out. ***the astericks are because the thermal conductivity of silicon is temperature dependent, the eq is: Kt =286/(T -100) for T =300 to 600K Cheers, jn |
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#398 | |
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diyAudio Member
Join Date: Oct 2008
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Quote:
I agree with everything you are saying here. I think your circuit is the most interesting here so far. I'll put it in to my simulator and have a closer look at it. BTW: is this the model you are using for the BF862? * BF862 SPICE MODEL MARCH 2007 NXP SEMICONDUCTORS * ENVELOPE SOT23 * JBF862: 1, Drain, 2,Gate, 3,Source Ld 1 4 L= 1.1nH Ls 3 6 L= 1.25nH Lg 2 5 L= 0.78nH Rg 5 7 R= 0.535 Ohm Cds 1 3 C= 0.0001pF Cgs 2 3 C= 1.05pF Cgd 1 2 C= 0.201pF Co 4 6 C= 0.35092pF JBF862 model parameters: .model JBF862 NJF(Beta=47.800E-3 Betatce=-.5 Rd=.8 Rs=7.5000 Lambda=37.300E-3 Vto=-.57093 + Vtotc=-2.0000E-3 Is=424.60E-12 Isr=2.995p N=1 Nr=2 Xti=3 Alpha=-1.0000E-3 + Vk=59.97 Cgd=7.4002E-12 M=.6015 Pb=.5 Fc=.5 Cgs=8.2890E-12 Kf=87.5E-18 + Af=1) ENDS BF862 Cheers Stein |
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#399 |
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#400 | |
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diyAudio Member
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