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#61 | |||
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diyAudio Member
Join Date: Jan 2004
Location: away
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Quote:
A thinner conductor will indeed have higher external inductance, this due to the higher current density. Quote:
Quote:
Well said.. Cheers, jn |
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#62 |
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diyAudio Member
Join Date: Jun 2007
Location: Blackburn, Lancs
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Its just a link to his site Andrew, just use back space eh!
home page Basicly they are the two of the most highly regarded people regarding shielding, EMC and grounding in the world, it only takes a bit of effort to register and you will be able to access a whole host of information covering what is being discussed. At the end of the day, ALL the experts in the field recomend shielding connected at both ends for rf... |
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#63 |
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diyAudio Member
Join Date: Jul 2004
Location: Scottish Borders
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Marce.
I asked two questions. Which tech tip? There are dozens in the list, but none jump out and say "this is me". Register here? I cannot proceed with your second link until I have a registration code. |
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#64 |
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diyAudio Member
Join Date: Jun 2007
Location: Blackburn, Lancs
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The best bet with H. Ott is get his book electromagnetic compatability engineering, chapter 3 covers grounding, chapter 6 covers shielding.
You dont require a registration code for the EMC club, just sign up. Heres one article of interest from H. Ott site. http://www.hottconsultants.com/pdf_files/ground.pdf |
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#65 | |
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diyAudio Member
Join Date: May 2007
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Quote:
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#66 |
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diyAudio Member
Join Date: Jul 2004
Location: Scottish Borders
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Marce,
thanks for the OTT link. I will read through and probably some others. On reading the conclusion, I see I am one of the converted. I harp on about currents regularly, particularly what route the current returns by. For every Flow there must be a Return, otherwise circuits cannot exist. |
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#67 | ||
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diyAudio Member
Join Date: Jan 2004
Location: away
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Quote:
When I built the code to calculate the inductance of only 1 conductor with no return in a thin sectional length of wire, no matter how far out in space I went, the integrated field energy kept going up. Only makes sense, as doubling the distance of each thin shell doubled it's length, and the field falls as 1/r so halved. Each shell always had the same total energy..duh.. Quote:
Cheers, jn |
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