Does this circuit have gain?

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Hello.

This is a circuit for a Samson C02 microphone that was brought by a generous contributor who I'd credit if I remembered who it was but this will have to do.

http://ap23-images.s3.amazonaws.com/samson-co2.jpeg

I would like to use it as a general purpose single-to-balanced converter. I can provide the phantom voltage. It would be handy, though, if it had gain, and I'm not smart enough to look at it and make any educated guess whether it does.

Is there anyone out there who could look at this and make such a guess? Or who knows whether microphone circuits like this characteristically have gain? And even maybe a guess as to how much, generally?

Thank you.

B
 
Thank you.

I wonder whether I could add a gain stage somewhere. Maybe decrease R4 so I can pull 9V for an input stage. I don't need super high impedance.

Depending of the technology you want to use (Bipolar, JFET, MOSFET, Tubes, opamps.), then you can add the gain in the stage following this, or in another preceding. This depends on if you want to get amplifier symmetrical or single ended. A simple stage that can do both in the same stage is the companion picture. R1 must be equal, and aproximate to the specified mic load (47Kohms??) and eventually you can put here a capacitor to tune the mic, in case of magnetic one. The stage gain is about (2R4/R2) +1 and R2 may be variable to adjust gain. Also, here, in // to R4 you can add tone compensation networks as desired, symmetrically placed on both R4's. Of course, you can use another opamp of your taste.

Use split power source (As example, 2 9V batteries), correctly decoupled, or single supply, tying the ground to a voltage divider at 1/2 VCC. This schematic has both, low output impedance, and as gain as you need for normal purposes.
 

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Rather than me trying to explain it in words, here's a very simplified form of the phantom power source in a Mic preamp. Put it up against the right hand side of the post #1 circuit to see how the DC current flows.
This is the standard 48V phantom power method used for balanced condenser mics the world over (there are other types)
The answer to your original Q is that the return path is through the Zener and the FET via its drain and scource R's
 

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I would not design the circuit with Ic controlled with a single resistor (R5 / R6)
But that is just me.:)

In its defence, it doesn't have to ouptut much signal - about 1V absolute max.
It's based on the circuit in the Schoeps CMC-5 mic body below.
The extra circuitry at the bottom is the 60V bias supply for the condenser mic capsule. The Samson CO2 doesn't need it as it's an electret mic.
 

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EssB, Is this an example of the circuit inside the mic preamp for the P48, or is this supposed to be within the mic circuit in order to receive P48 from the mic pre? I have seen this before, I am just confused by this context. Thanks!

Rather than me trying to explain it in words, here's a very simplified form of the phantom power source in a Mic preamp. Put it up against the right hand side of the post #1 circuit to see how the DC current flows.
This is the standard 48V phantom power method used for balanced condenser mics the world over (there are other types)
The answer to your original Q is that the return path is through the Zener and the FET via its drain and scource R's
 
That is the circuit inside the mic preamp, not the one inside the mic.

I would note that there is a subtle issue with P48 in that a cable going short can dump the charge on the preamp input coupling caps into the preamp input base/emitter junction which is not a healthy failure mode.
There are ways of dealing with it, but it does need consideration.

Regards, Dan.
 
Just to be clear (as people often refer to the mic's internal amplifier as a mic pre), you mean that is the power circuit inside of the mic pre that provides P48 to the mic's internal amp through the XLR connection and not the circuit inside the mic's internal amplifier, correct?
 
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