Burning Amplifier BA-2

Hi,
two of these, one on top of the other will increase dissipation by about 40%.
Two side by side or back to back will increase dissipation by ~100%.

Side by side spaces the FETs too far apart.
Back to back with the sinks clamping the devices would work if this is the top most part of the amplifier.

Two channels at full bias would probably require 4 of those sinks.
 
As you can see there are two of these heatsinks bolted together.
Chris
 

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I didn't think they would have the data but they have. Well done MODU.

The data (which is attached) for a heatsink 400x 160x 40, (which means two of the 200x160x40 bolted to a joining bracket), at 25 degrees C ambient and Rt((degrees C/W) of 0.23.
For a TO3-P device, multiplied by 6, Max power dissipation (6xTO3-P) is 375W per heatsink.
 

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Having looked through Farnell heatsinks I have found one that looks very similar to those on the other chassis I was hoping to use for the amp.
This chassis has smaller heatsinks than the MODU design, measuring 300 width, 120 depth and 40 height similar to Forsman's.
I am getting a K/W of about 0.35 for this heatsink, looking at the graph supplied on the datasheet from Farnell.
 
delta T s-a = Rth s-a * P
Ta = ambient.

375W into a pair of sinks gives delta T s-a ~ 86C
When room is hot say Ta=30degC the heatsink will be at 116degC and Tc ~130degC.

0.23C/W does not come close to being adequate.
Does each in the 6pair dissipate >30W?
 
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Sorry Andrew. I was writing down what was on the MODU datasheet without understanding it. I don't know where the 375W comes from.
Let me put it another way. If I put the BA-2 Mosfets on this heatsink will it cope because I thought that we were looking for about 75W dissipation?
Best wishes,
Chris
 
At Pass Laboratories read the A75 part 2 article. There is a good discussion of how to calculate how much heat sink you'll need. It boils down to adding thermal resistances, multiplying the sum by the power dissipated to determine the temperature rise. Given a temperature rise of 30C, you can rearrange the equation to determine the needed heat sink thermal resistance. There are other places on the web that present it differently if you cannot wrap your head around Papa's explanation. Rod Elliot's site and the LM3886 data sheet are two I know of.